Freshman year I took Algebra 1 in Salem, New hampshire, I did very well in the class and had good test scores but missed my final and wasn't aloud to retake it so I faild because it was a major part of my grade. Sophomore year I was demoted to Algebra 1A Concepst, not because I couldn't do the work but because I needed a smaller class room according to my IEP. About half way through the year I transfured to a school in Katy, Texas but didn't stay long. By the end of that same school year I transfured to Somerville, MA. To start school there after that summer as a junior taking geometery. Currently, I am A Senior taking Algebra 2, I'm really hoping this will be my last year of high school. College isn't comming soon enough and I need this class to graduate. Math is easy but i like to challenge myself sometimes because it comes so naturally. In my expirence, very specific notes, clear directions, and asistance are the best methods to ensure understanding in a positive/effective way.
1.2
In step 1 the equation is presented to solve. In step 2 multiply the bracketed individually by ten to simplify the equation so theirs longer fractions in step 3. Step 3s equation is now in simplist form, leaving the first pair of like terms to be subtracted from each other. Step 4 is simply subtracting the second pair of like terms from each other. Step 5 solving for x,
divide the result of the first liked term by the result of the second liked term. step 6 Is the anwser to the divided terms of step 5. step 7 is to check your work, so you take the original problem,which is shown in step 1, and replace the x place holder with step 6. Step 8 is a simplified version of step 7, like step 3 a simpler version of step 2. Step 9 proves that step 6 is right, when step 9 shows both equations on opposite sides of the equal sign with the same number.
1.3
1.4
Linear Function- constructing a table of values where m and b are constants and the ploted points of a line form a slope line
Relation- pairing of domain with the range. relation is a function when no vertical line intersects the graph of the relation at more than one point.
Domain- input value of relation
Range- output value of relation
Increasing- more, positive slope climbs from right to left
Decreasing- less, negative slope falls from left to right
Slope- a lines rate of change determined by the rise in vertical change to the run in horizontal change
Intercept-
Degree-
1.5
In your own words describe what a relation is and a linear function is.
Give an example of a relation that is a function and a relation that is not a function. Represent the relation graphically and as a set of coordinate points. Explain why your second example is not a function. You cannot use example 2 on page 68 as your example.
Give an example of a linear function written in function notation. Identify the slope and y-intercept of the function. Graph the function and label at least 3 coordinate point that are on the line. You cannot use example 4 on page 69 as your example.
1.1
Freshman year I took Algebra 1 in Salem, New hampshire, I did very well in the class and had good test scores but missed my final and wasn't aloud to retake it so I faild because it was a major part of my grade. Sophomore year I was demoted to Algebra 1A Concepst, not because I couldn't do the work but because I needed a smaller class room according to my IEP. About half way through the year I transfured to a school in Katy, Texas but didn't stay long. By the end of that same school year I transfured to Somerville, MA. To start school there after that summer as a junior taking geometery. Currently, I am A Senior taking Algebra 2, I'm really hoping this will be my last year of high school. College isn't comming soon enough and I need this class to graduate. Math is easy but i like to challenge myself sometimes because it comes so naturally. In my expirence, very specific notes, clear directions, and asistance are the best methods to ensure understanding in a positive/effective way.1.2
In step 1 the equation is presented to solve. In step 2 multiply the bracketed individually by ten to simplify the equation so theirs longer fractions in step 3. Step 3s equation is now in simplist form, leaving the first pair of like terms to be subtracted from each other. Step 4 is simply subtracting the second pair of like terms from each other. Step 5 solving for x,divide the result of the first liked term by the result of the second liked term. step 6 Is the anwser to the divided terms of step 5. step 7 is to check your work, so you take the original problem,which is shown in step 1, and replace the x place holder with step 6. Step 8 is a simplified version of step 7, like step 3 a simpler version of step 2. Step 9 proves that step 6 is right, when step 9 shows both equations on opposite sides of the equal sign with the same number.
1.3
1.4
1.5
- In your own words describe what a relation is and a linear function is.
- Give an example of a relation that is a function and a relation that is not a function. Represent the relation graphically and as a set of coordinate points. Explain why your second example is not a function. You cannot use example 2 on page 68 as your example.
- Give an example of a linear function written in function notation. Identify the slope and y-intercept of the function. Graph the function and label at least 3 coordinate point that are on the line. You cannot use example 4 on page 69 as your example.